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The 12 Steps Recipe for 5% Lugol’s 200 mL
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Published: 5 years ago
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The 12 Steps Recipe for 5% Lugol’s 200 mL

The 12 Steps Recipe for 5% Lugol’s 200 mL

1. Obtain a clean, empty 250 mL glass amber boston round bottle and black cap.
(wash everything with hot soapy water & rinse with small amounts of distilled water)

2. Carefully measure exactly 200 mL tap water into the bottle.

3. Level bottle, then mark water level with permanent marker & cover mark with clear tape.

4. Empty & rinse bottle with a small amount of distilled water.

5. Add about 150 mL distilled water to the empty bottle.

6. Weigh & add 20.00 grams of potassium iodide.

7. Cap bottle & rotate/shake until dissolved.

8. Weigh then add 10.00 grams of elemental Iodine crystal.

9. Cap bottle & rotate/shake to start dissolving the Iodine.

10. Let it set 2-3 days, rotating (etc) occasional until all is dissolved (I use a flashlight).

11. After all is dissolved, carefully add distilled water exactly to the 200 mL mark from steps 2-3 above.

12. Label your bottle with the above weights, volumes, whether 5% etc.

The above recipe will give 6.323 mg I per .05 mL (using .7645 I from KI)

I also calibrate my droppers and write the REAL volume & weight / drop on my bottle labels along with the weights / .05 mL etc.

NOTE: Drop size will probably change after exposure to magnets, if you use them.

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